mi da errore Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/raptxt/public_html/commenti.php on line 26 (la riga del while)
e mi mostra solo l'ultimo elemento della tabella del db e non tutti...
Codice PHP:
<?php session_start();
// Get the default templates, Includes and Database connections
include("header.php");
$tpl->assignInclude("content", "themes/$themes/tpl/commenti.tpl");
// Prepare the template
$tpl->prepare();
// Get the menu items and links
include("menu.php");
// Assign needed values
$tpl->assignGlobal("theme", $themes);
$tpl->assignGlobal("imgfolder", "http://raptesti.interfree.it");
$tpl->assign("version", $version);
$tpl->assign("type", $_GET['art']);
$a=1;
// The MySQL command to run
$select = "SELECT * FROM commenti WHERE alb=$alb ORDER BY data, uid ASC";
// Run the query
$data = mysql_db_query($sql['data'], $select) or die("commenti Failed!");
while ($row = mysql_fetch_array($data))
{
// Get all the fields
$uid = $row['uid'];
$nome = $row['nome'];
$data = $row['data'];
$commento = $row['commento'];
echo"$nome $commento";
$nome=stripslashes($nome);
$commento=stripslashes($commento);
$commento=nl2br($commento);
$rap="";
if ($nome =="" || $commento=""){
$nome="RapTxt"; $commento="nessun commento inserito. Inserisci tu il primo!";}
// Set the values to template variables
$tpl->newBlock("commenti");
$tpl->assign("uid", $uid);
$tpl->assign("nome", $nome);
$tpl->assign("commento", $commento);
$tpl->assign("data", $data);
$tpl->assign("num", $a);
$a++;
}
// Print the result
$tpl->printToScreen();
?>