ho un errore esattamente, mi visualizza sempre error.. la connesione è giusta </html>
non capisco.. lo controllato mille volte il file e non trovo l'errore.. aiuto
Codice PHP:<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Admin Lega / Mail list</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>
<?
include "connect.php";
/*Form*/
function form()
{
print "<form action=\"?action=form_ok\" method=\"post\">
<table align=\"center\" style=\"border:1px solid #000000\"><tr bgcolor=\"#CCCCCC\"><td colspan=\"2\"><div align=\"center\">[b]LOGIN[/b]</div></td>
</tr><tr>
<td>Username:</td><td> <input type=\"text\" name=\"user\"></td></tr>
<tr><td>Password:</td><td> <input type=\"password\" name=\"password\"></td></tr>
<tr bgcolor=\"#CCCCCC\"><td colspan=\"2\" align=\"center\">
<input type=\"submit\" value=\"Accedi\" style=\"border:1px solid #CCCCCC\">
</td>
</tr></table>
</form>";
};
function form_ok(){$us_admin = xxx; // Username dell'admin
$pass_admin = xxx; // Password dell'admin
/* controllo */
if ($user == "$us_admin" AND $password == "$pass_admin")
{
$query = "SELECT * FROM lega ";
$result = mysql_query($query) or die (mysql_error());
while($query_data = mysql_fetch_array($result))
{$id = $query_data["id"];
$email = $query_data["email"];
echo"$email, ";
}
}
else
{echo"error";};}
switch ($action)
{
case 'form_ok' : form_ok();break;
default: form();
}
?>
<body>
</body>
</html>
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