Ciao gente,
sto dando un'occhiata all'esempio di file web.xml disponibile con la versione di Tomcat 5.0.
Tutto chiaro, meno che per questa parte:
codice:
    <servlet>
      <servlet-name>controller</servlet-name>
      <description>
        This servlet plays the "controller" role in the MVC architecture
        used in this application.  It is generally mapped to the ".do"
        filename extension with a servlet-mapping element, and all form
        submits in the app will be submitted to a request URI like
        "saveCustomer.do", which will therefore be mapped to this servlet.

        The initialization parameter namess for this servlet are the
        "servlet path" that will be received by this servlet (after the
        filename extension is removed).  The corresponding value is the
        name of the action class that will be used to process this request.
      </description>
      <servlet-class>com.mycompany.mypackage.ControllerServlet</servlet-class>
      <init-param>
        <param-name>listOrders</param-name>
        <param-value>com.mycompany.myactions.ListOrdersAction</param-value>
      </init-param>
      <init-param>
        <param-name>saveCustomer</param-name>
        <param-value>com.mycompany.myactions.SaveCustomerAction</param-value>
      </init-param>
      
      <load-on-startup>5</load-on-startup>
    </servlet>
aiutatemi a capire; questo è il controller principale della mia web-app, ed è incaricato di smistare le chiamate ad altri due servlet (listorders, savecustomer).
codice:
    <servlet-mapping>
      <servlet-name>controller</servlet-name>
      <url-pattern>*.do</url-pattern>
    </servlet-mapping>
Ma non ho capito come?? :master: