[neofita] info su printf

[chisono]

salve gente

mi spiegate questo:
\t6%u\

in una funzione printf

mi produce un codice tipo 645467324562

la "t" lascia un tab
mentre il "6" si và a porre davanti al numero generato da %u

adesso vorrei eliminare il il TAB, come devo fare?
togliendo la t mi dà errore.

grazie

[luke83]

% - a literal percent character. No argument is required.
b - the argument is treated as an integer, and presented as a binary number.
c - the argument is treated as an integer, and presented as the character with that ASCII value.
d - the argument is treated as an integer, and presented as a (signed) decimal number.
u - the argument is treated as an integer, and presented as an unsigned decimal number.
f - the argument is treated as a float, and presented as a floating-point number.
o - the argument is treated as an integer, and presented as an octal number.
s - the argument is treated as and presented as a string.
x - the argument is treated as an integer and presented as a hexadecimal number (with lowercase letters).
X - the argument is treated as an integer and presented as a hexadecimal number (with uppercase letters).
sostituisci uno di questi alla t...

se nn va posta l'errore esatto che ti dà il parser

[chisono]

ho risolto mettendo semplicemente

6%u

invece di
\6%u\



grazie mille, il tuo aiuto è stato decisivo.

[luke83]

uh? :master:

ok.. ciaone