Ciao eseguendo questo codice in php:
<?php ---------------------------------
require ("Connessionearbitro.php");
$query = "select idS,idP from Squadra,Partita where Partita.in-casa=Squadra.nome;";
$result = mysql_query($query, $conn);
while ($line=mysql_fetch_array($result, MYSQL_NUM)) {
$query2 = "insert into Gioca (idS,idP,data) VALUES ('$line[0]','$line[1]','1/10/2009');";
$result2 = mysql_query($query2,$conn);
}
mysql_close($conn);
?> ----------------------------------------------
mi da questo tipo di errore:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource on line 9
Perchè????