VI POSTO TUTTO CHE FACCIAMO PRIMA, non capisco questi errori, posto anche il codice, è un form di registrazione.
Praticamente i dati inseriti non mi vengono inviati nel database in locale chiamato utenti con tabella 'dati'

codice:
Warning: mysql_connect() [function.mysql-connect]: php_network_getaddresses: getaddrinfo failed: Host sconosciuto. in C:\Program Files\EASYPHP\www\gate.php on line 54

Warning: mysql_connect() [function.mysql-connect]: [2002] php_network_getaddresses: getaddrinfo failed: Host sconosciuto. (trying to connect via tcp://locahost:3306) in C:\Program Files\EASYPHP\www\gate.php on line 54

Warning: mysql_connect() [function.mysql-connect]: php_network_getaddresses: getaddrinfo failed: Host sconosciuto. in C:\Program Files\EASYPHP\www\gate.php on line 54

Warning: mysql_select_db() [function.mysql-select-db]: Access denied for user ''@'localhost' (using password: NO) in C:\Program Files\EASYPHP\www\gate.php on line 55

Warning: mysql_select_db() [function.mysql-select-db]: A link to the server could not be established in C:\Program Files\EASYPHP\www\gate.php on line 55

Warning: mysql_query() [function.mysql-query]: Access denied for user ''@'localhost' (using password: NO) in C:\Program Files\EASYPHP\www\gate.php on line 57

Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\Program Files\EASYPHP\www\gate.php on line 57
Codice PHP:
<?PHP
        
        $SUB 
$_POST['INVIA'];
        
$NOM $_POST['NOME'];
        
$COG $_POST['COGNOME'];
        
$GG $_POST['GG'];
        
$MM $_POST['MM'];
        
$AAAA $_POST['AAAA'];
        
$SEX $_POST['SESSO'];
        
$COD1 $_POST['CODICE1'];
        
$COD2 $_POST['CODICE2'];
        
$EMAIL $_POST['EMAIL'];

        IF (
$SUB) {
            
            IF (
$NOM&&$COG&&$GG&&$MM&&$AAAA&&$SEX&&$COD1&&$COD2&&$EMAIL) {
                    
                IF (
$COD1==$COD2) {
                    
                    
$CON mysql_connect('locahost','root','');
                
mysql_select_db('utenti');
                
                
$QUERY mysql_query("INSERT INTO dati VALUES ('','$NOM','$COG','$COD1','$EMAIL')");
                    ECHO 
'SEI DENTRO!';
                    
                } ELSE {
                    ECHO 
'ERRORE, I DUE CODICI NON RISULTANO UGUALI';
                }
            
            } ELSE {
                ECHO 
'ERRORE, CONTROLLA I DATI INSERITI';
            }
            
        } ELSE {
        
        }
        
    
?>
Chiedo umilmente aiuto!