Vorrei sapere perche in base al codice riportato sotto l' immagine descr0.jpg, quando ca mbio la risoluzione delloo schermo non rimane nella posizione che gli ho dato.
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<HEAD><TITLE>Farmatech itaLia</TITLE>
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<SCRIPT LANGUAGE = "JavaScript">
<!--
t0 = new Image(); t0.src ="img/descr0.jpg";
ta = new Image(); ta.src ="img/descr1.jpg";
tb = new Image(); tb.src ="img/descr2.jpg";
tc = new Image(); tc.src ="img/descr3.jpg";
td = new Image(); td.src ="img/descr4.jpg";
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img1 = eval(imgName + ".src");
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document ["t0"].src = img2;
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</HEAD>
<BODY bgcolor="#bcb5b6" TEXT="#000080" LINK="#FF0000" VLINK="#FF0000" MARGINWIDTH="0" MARGINHEIGHT="0" topmargin="0" leftmargin="0">
<map NAME="ICT">
<area SHAPE="RECT" COORDS="10,135,107,168" HREF="azienda/index.htm" onMouseover = "inactive('ta')" onMouseout = "active('t0')">
<area SHAPE="RECT" COORDS="8,206,115,240" HREF="prodotti/index.htm" onMouseover = "inactive('tb')" onMouseout = "active('t0')">
<area SHAPE="RECT" COORDS="12,276,110,308" HREF="contatti/index.htm" onMouseover = "inactive('tc')" onMouseout = "active('t0')">
<area SHAPE="RECT" COORDS="167,377,310,412" HREF="mailto:info@farmatech.it" onMouseover = "inactive('td')" onMouseout = "active('t0')">
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[img]img/copertina.jpg[/img]
<DIV ID="t0" STYLE="position:absolute; left:400px; top:115px; width:290"> [img]img/descr0.jpg[/img]
</DIV>
<DIV ID="conta" STYLE="position:absolute; left:630; top:385; width:110">
<font COLOR="#FFFFff" size="2">visitato 32178 volte</font>
</DIV>
</BODY>
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Grazie
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