Salve, con un form vorrei fare l'upload di un file fisicamente in una cartella creata sul server e registrare il percorso in un dbase access; ho costruito il form e richiamo la classe con questo code, che però non fa nessuna operazione e non restituisce però nessun errore, qualcuno ha un'idea perchè non funziona?:

codice:
<%

Dim DestinationPath
DestinationPath = Server.mapPath(VirtualFolder) & "\"

Dim Form: Set Form = New ASPForm %><% 

Server.ScriptTimeout = 2000
Form.SizeLimit = &HA00000


if len(Request.QueryString("titolo"))>0 then
	Form.UploadID = Request.QueryString("titolo")
end if


If Form.State = 0 Then 'Completted

  Const VirtualFolder = "UploadFolder"

  Dim File, DestFileName
  For Each File In Form.Files.Items
		If Len(File.FileName) > 0 Then
        DestFileName = GetUniqueFileName(File.FileName, DestinationPath)

        File.SaveAs DestinationPath & "\" & DestFileName
           Response.Write "La procedura ha avuto esito Positivo ! " & "

"
            Response.Write "Il seguente File:<Font Color=red> " & File.FileName & "</Font>" & " é stato regolarmente inviato al server ed i dati in esso contenuti sono stati importati nel Database Nazionale. 

" 
            '& DestinationPath & " </Font>" & "

"
					'con questo nome " & DestFileName & "</Font>" & "

"

	  End If
  Next
  
  
    Dim virtDestinationPath
  virtDestinationPath = "http://" + Request.ServerVariables("SERVER_NAME") _
   + GetPath(Request.ServerVariables("SCRIPT_NAME") ) _
   + "/" + VirtualFolder + "/"

    Dim FileField
  For Each FileField in Form.Files.Items
    
    if len(FileField.FileName)> 0 then 
      Dim DestinationFileName

      DestinationFileName = DestinationPath & FileField.FileName

      FileField.SaveAs DestinationFileName
      
      Dim Conn, RS, oRs, intCount, numRecords
      intCount=0
      DestinationFileName = "UploadFolder/" & Form("File1").FileName
      Set Conn = GetConnection 

      Set oRs = Server.CreateObject("ADODB.Recordset")
  
  oRS.Open "ListFiles", GetConnection, 2, 2

     
   Do Until oRs.Eof 
          
      oRS.AddNew
          
       oRS("percorso") = virtDestinationPath & DestFileName
       oRS("titolo") = Form("titolo")
             
    oRs.Update
    intCount = intCount + 1

    
    oRs.MoveNext   
    Loop 
          
  oRs.Close
  Set oRs = Nothing   
  Conn.Close
  Set Conn = Nothing    
  
  end if
  Next 

  
ElseIf Form.State > 10 then
  Const fsSizeLimit = &HD
  Select case Form.State
		case fsSizeLimit: response.write  "
<Font Color=red>Source form size (" & Form.TotalBytes & "B) exceeds form limit (" & Form.SizeLimit & "B)</Font>
"
		case else response.write "
<Font Color=red>Some form error.</Font>
"
  end Select
End If'Form.State = 0 then

Dim gFS
Function GetUniqueFileName(FileName, DestPath)
  if isempty(gFS) then Set gFS = CreateObject("Scripting.FileSystemObject")
  Dim Counter, FullPath, NewFileName
  Counter = 1
  NewFileName = FileName
  
  if gFS.FileExists(DestPath & "\" & NewFileName) then
		Do 
			Counter = Counter + 1
			NewFileName = Counter & "_" & FileName
		Loop while gFS.FileExists(DestPath & "\" & NewFileName)
  end if
  GetUniqueFileName = NewFileName
End Function


Function GetConnection()
  dim Conn: Set Conn = CreateObject("ADODB.Connection")
  Conn.Provider = "Microsoft.Jet.OLEDB.4.0"
  Conn.open "Data Source=" & Server.MapPath("upload.mdb") 
  set GetConnection = Conn
end function

Function SplitFileName(FullPath)
  Dim Pos, PosF
  PosF = 0
  For Pos = Len(FullPath) To 1 Step -1
    Select Case Mid(FullPath, Pos, 1)
      Case ":", "/", "\": PosF = Pos + 1: Pos = 0
    End Select
  Next
  If PosF = 0 Then PosF = 1
 SplitFileName = PosF
End Function

Function GetPath(FullPath)
  GetPath = left(FullPath, SplitFileName(FullPath)-1)
End Function

%>