data in italiano

[cubalibre810]

$sql = "SELECT nometabella.*, DATE_FORMAT(nometabella.data1, '%d-%m-%Y')AS data1, DATE_FORMAT(nometabella.data2, '%d-%m-%Y')AS data2, DATE_FORMAT(nometabella.data3, '%d-%m-%Y')AS data3
        FROM nometabella
        WHERE id_serviziunghie=$contatto";
    $result = mysql_query($sql,$conn);
    $row = mysql_fetch_array($result);