ciao la classe e :
Codice PHP:

    function query($sql) {
        $result = mysql_query($sql,$this->dbcore);

        return $result;
    }
    function insert_id(){
    $result = $this->query($sql);
    $id = mysql_insert_id();
    return $id;
    }
    
    function getrow($sql) {
        $result = $this->query($sql);
        $returned = mysql_fetch_assoc($result);
        @mysql_free_result($result);
        return $returned;
    }
    
    function getlist($sql) {
        $returned = array();
        $result = $this->query($sql);
        while ($row = mysql_fetch_assoc($result)) {
            $returned[] = $row;
        }
        
        @mysql_free_result($result);
        return $returned;
    }
    
    function getnumrows($sql) {
        $result = $this->query($sql);
        $num = mysql_num_rows($result);
        @mysql_free_result($result);
        return $num;
    } 
l errore e:Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in C:\Programmi\Apache Software Foundation\Apache2.2\htdocs\supp\includes\function _db.php on line 75

la riga 75 e while ($row = mysql_fetch_assoc($result)) {