Creare dinamicamente un xml con php

[gaten]

Risolto così:

<?php
header ("content-type: text/xml");

include("connessione.php");

$sql="SELECT * FROM `categoria` ORDER BY `id_categoria` ASC";

$result = mysql_query($sql) or die ("Errore query: ".mysql_query($sql));

$xml = '<gallery title="Modula Gioielli" thumbDir="http://'.$_SERVER['SERVER_NAME'].'/images/" imageDir="http://'.$_SERVER['SERVER_NAME'].'/images/" random="true">';

while($category = mysql_fetch_assoc($result)){
    $xml .= '<category name="'.$category['nome'].'">';
    $result2 = mysql_query("SELECT * FROM `immagine` WHERE `id_categoria` = '".$category['id_categoria']."' ORDER BY `id_immagine` ASC");
        while($image = mysql_fetch_assoc($result2)){
            $xml .= "<image>";
            $xml .= "<date>".$image['data']."</date>";            
            $xml .= "<title>".$image['titolo']."</title>";
            $xml .= "<desc>".$image['descrizione']."</desc>";
            $xml .= "<thumb>".$image['path']."</thumb>";            
            $xml .= "<img>".$image['path']."</img>";
            $xml .= "</image>";
        }
    $xml .= "</category>";
}

$xml .= '</gallery>';

$XMLFile = fopen("gallery.xml","w") or die("ERRORE: Non posso aprire il file!");
fwrite($XMLFile, $xml);
fclose($XMLFile);
?>

;

Grazie a tutti!