Ho inserito nel form questa parte di codice per gestire l'apertura di file ma mi segnala l'errore sui parametri della ShellExecute,
precisamente sul Me. Why????


Public Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long


Dim RetVal As Long
RetVal = ShellExecute(Me.hwnd, "open", App.Path & "\help sorg\HELP.HLP", "", "", 1)