Menu XML caricato in un filmato

[negatyve]

ok, supponendo che il codice sia nella root del filmato esterno, cambialo con:

sectionNames = new Array();
sectionLinks = new Array();
var menuSpacing = 20;
mio_xml = new XML();
mio_xml.path = this;
mio_xml.ignoreWhite = true;
mio_xml.onLoad = function(success)
{
	if (success) {
		var nodes = this.firstChild.childNodes;
		for (var i = 0; i < nodes.length; i++) {
			var button_i = nodes[i].attributes.label;
			var links_i = nodes[i].attributes.link;
			sectionNames.push(button_i);
			sectionLinks.push(links_i);
			//trace(sectionNames[i]); 
		}
	} else {
		//this.path.labelName = "Caricamento Errato"; 
	}
	sectionCount = sectionNames.length;
	for (var i = 0; i <= sectionCount; i++) {
		this.path.menu.menuItem.duplicateMovieClip("menuItem_" + i, i);
		this.path.menu["menuItem_" + i].labelName = sectionNames[i - 1];
		this.path.menu["menuItem_" + i].link = sectionLinks[i - 1];
		this.path.menu["menuItem_" + i]._y = spazio;
		if (i != 1) {
			this.path.menu["menuItem_" + i]._y = this.path.menu["menuItem_" + (i - 1)]._y + this.path.menu["menuItem_" + (i - 1)].height + menuSpacing;
		}
	}
};
mio_xml.load("menu_azienda.xml");