Ciao a tutti da internet ho trovato questa funzione
ma non riesco ad utilizzarla....
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Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long
Sub OpenFile(hwnd As Long, File As String, Optional Operation As String = "open", Optional Param As String = "", Optional Dir As String = "")
Call ShellExecute(hwnd, Operation, File, Param, Dir, 1)
End Sub
OpenFile Me.hwnd, "C:\Documenti\Pippo.txt"
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Devo lanciare un file prova.apr con il programma approach.exe
sapete dove sbaglio
openfile approach.exe, "open", pathfile
mi dà errore 424 su approach.exe
se scrivo invece :
openfile me.hwnd, "open" , pathfile
non succede completamente nulla
ringrazio tutti per la partecipazione...