Grazie Ken84 ma ora mi da altri errori...
Warning: Cannot use a scalar value as an array .... on line ....
(line di riferimento - $query[] = "(fname LIKE '%$chiave%'...)
Warning: implode(): Bad arguments. in ... on line ...
(line di riferimento - $query_string = " ...)
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in ... on line 313 ...
(line riferimento - while ($row = mysql_fetch_array ($dati)){ ...)