Per ottenere la data e l'ora attuale in un formato gestibile ti puoi basare su questo codice.
codice:
TYPE DateTime
Year AS INTEGER
Month AS INTEGER
Day AS INTEGER
Hour AS INTEGER
Minutes AS INTEGER
Seconds AS INTEGER
END TYPE
DECLARE SUB GetDateTime (dt AS DateTime)
DIM dt AS DateTime
GetDateTime dt
PRINT dt.Year, dt.Month, dt.Day, dt.Hour, dt.Minutes, dt.Seconds
SUB GetDateTime (dt AS DateTime)
'Qui ci sarebbe una race condition... :-(
mdate$ = DATE$
mtime$ = TIME$
dt.Month = VAL(LEFT$(mdate$, 2))
dt.Day = VAL(MID$(mdate$, 4, 2))
dt.Year = VAL(RIGHT$(mdate$, 4))
dt.Hour = VAL(LEFT$(mtime$, 2))
dt.Minutes = VAL(MID$(mtime$, 4, 2))
dt.Seconds = VAL(RIGHT$(mtime$, 2))
END SUB