Ciao a tutti,
premettendo la niubbagine sull'argomento, ho un problema con il caricamento di un documento XML in JSP.
Il codice l'ho preso da un esempio banale riportato in tantissimi forum/libri/documenti quindi non capisco perchè non funzioni.
Il file JSP è:
Mentre l'XML è:codice:<%@ page contentType="text/html" %> <%@ taglib prefix="c" uri="http://java.sun.com/jstl/core" %> <%@ taglib prefix="x" uri="http://java.sun.com/jsp/jstl/xml" %> <html> <body> <c:import url="books.xml" var="url" /> <x:parse xml="${url}" var="doc" /> <x:forEach var="n" select="$doc/books/book"> <x:out select="$n/title" /> <x:out select="$n/author" /> </x:forEach> </body </html>
In esecuzione l'errore che ricevo è il seguente:codice:<?xml version="1.0" ?> <books> <book> <title>cobol</title> <author>roy</author> </book> <book> <title>java</title> <author>herbert</author> </book> </books>
exception
org.apache.jasper.JasperException: javax.servlet.ServletException: javax.servlet.jsp.JspException: org.xml.sax.SAXParseException: Content is not allowed in prolog.
org.apache.jasper.servlet.JspServletWrapper.handle JspException(JspServletWrapper.java:527)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:401)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
root cause
javax.servlet.ServletException: javax.servlet.jsp.JspException: org.xml.sax.SAXParseException: Content is not allowed in prolog.
org.apache.jasper.runtime.PageContextImpl.doHandle PageException(PageContextImpl.java:858)
org.apache.jasper.runtime.PageContextImpl.handlePa geException(PageContextImpl.java:791)
org.apache.jsp.index2_jsp._jspService(index2_jsp.j ava:91)
org.apache.jasper.runtime.HttpJspBase.service(Http JspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
root cause
org.xml.sax.SAXParseException: Content is not allowed in prolog.
com.sun.org.apache.xerces.internal.parsers.DOMPars er.parse(Unknown Source)
com.sun.org.apache.xerces.internal.jaxp.DocumentBu ilderImpl.parse(Unknown Source)
org.apache.taglibs.standard.tag.common.xml.ParseSu pport.parseInputSource(Unknown Source)
org.apache.taglibs.standard.tag.common.xml.ParseSu pport.parseInputSourceWithFilter(Unknown Source)
org.apache.taglibs.standard.tag.common.xml.ParseSu pport.parseReaderWithFilter(Unknown Source)
org.apache.taglibs.standard.tag.common.xml.ParseSu pport.parseStringWithFilter(Unknown Source)
org.apache.taglibs.standard.tag.common.xml.ParseSu pport.doEndTag(Unknown Source)
org.apache.jsp.index2_jsp._jspx_meth_x_005fparse_0 05f0(index2_jsp.java:140)
org.apache.jsp.index2_jsp._jspService(index2_jsp.j ava:77)
org.apache.jasper.runtime.HttpJspBase.service(Http JspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717
Qualcuno sa darmi una soluzione?
Grazie in anticipo
Rispondi quotando
