Salve a tutti.
Ho utilizzato una procedura per l'upload su server aruba composta da tre file da inserire nella cartella public.


1- form_upload_01.asp
..
..
..
<FORM METHOD="Post" ENCTYPE="multipart/form-data" ACTION="outputFile.asp" target="_blank">
<p align="center"><font face="Verdana" size="2">
File : <INPUT TYPE="file" NAME="blob">


<INPUT TYPE="submit" NAME="Enter" value="INVIA" align="middle">
</font>
</FORM>

2- upload.asp
<%Sub BuildUploadRequest(RequestBin)
PosBeg = 1
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
boundary = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
boundaryPos = InstrB(1,RequestBin,boundary)
Do until (boundaryPos=InstrB(RequestBin,boundary & getByteString("--")))
Dim UploadControl
Set UploadControl = CreateObject("Scripting.Dictionary")
Pos = InstrB(BoundaryPos,RequestBin,getByteString("Conte nt-Disposition"))
Pos = InstrB(Pos,RequestBin,getByteString("name="))
PosBeg = Pos+6
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
Name = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
PosFile = InstrB(BoundaryPos,RequestBin,getByteString("filen ame="))
PosBound = InstrB(PosEnd,RequestBin,boundary)
If PosFile<>0 AND (PosFile<PosBound) Then
PosBeg = PosFile + 10
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
FileName = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
UploadControl.Add "FileName", FileName
Pos = InstrB(PosEnd,RequestBin,getByteString("Content-Type:"))
PosBeg = Pos+14
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
ContentType = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
UploadControl.Add "ContentType",ContentType
PosBeg = PosEnd+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
Else
Pos = InstrB(Pos,RequestBin,getByteString(chr(13)))
PosBeg = Pos+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
End If
UploadControl.Add "Value" , Value
UploadRequest.Add name, UploadControl
BoundaryPos=InstrB(BoundaryPos+LenB(boundary),Requ estBin,boundary)
Loop
End Sub
Function getByteString(StringStr)
For i = 1 to Len(StringStr)
char = Mid(StringStr,i,1)
getByteString = getByteString & chrB(AscB(char))
Next
End Function
Function getString(StringBin)
getString =""
For intCount = 1 to LenB(StringBin)
getString = getString & chr(AscB(MidB(StringBin,intCount,1)))
Next
End Function%>

3- outputFile.asp

<%Response.Expires=0
Response.Buffer = TRUE
Response.Clear
byteCount = Request.TotalBytes
RequestBin = Request.BinaryRead(byteCount)
Dim UploadRequest
Set UploadRequest = CreateObject("Scripting.Dictionary")
BuildUploadRequest RequestBin
contentType = UploadRequest.Item("blob").Item("ContentType")
filepathname = UploadRequest.Item("blob").Item("FileName")
filename = Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
value = UploadRequest.Item("blob").Item("Value")

'Create FileSytemObject Component
Set ScriptObject = Server.CreateObject("Scripting.FileSystemObject")

'Create and Write to a File
pathEnd = Len(Server.mappath(Request.ServerVariables("PATH_I NFO")))-14
Set MyFile = ScriptObject.CreateTextFile(Left(Server.mappath(Re quest.ServerVariables("PATH_INFO")),pathEnd) & filename)

For i = 1 to LenB(value)
MyFile.Write chr(AscB(MidB(value,i,1)))
Next
MyFile.Close%>

<head>
<title></title>
</head>

<body bgcolor="#FFCB8C">

<p align="center"><font face="Verdana" size="2">
File "<%=filename%>" ricevuto con successo</font>
<p align="center"><font face="Verdana" size="2">torna</font></p>

Questa procedura funziona benissimo su un sito, mentre in un'altro mi da questo errore:

Microsoft VBScript runtime error '800a0005'
Invalid procedure call or argument
/public/outputFile.asp, line 23

22 For i = 1 to LenB(value)
23 MyFile.Write chr(AscB(MidB(value,i,1)))
24 Next

n.b. il file viene trasferito correttamente, ma non visualizza la pagina outputFile.asp

preciso che il server è sempre aruba.


Grazie a tutti anticipatamente

Roberto