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Discussione: Errore su upload

  1. #1

    Errore su upload

    Salve a tutti,

    non so cosa possa essere ma in uno script che ha se,pre funzionato da qualche giorno mi spunta questo errore:

    Microsoft VBScript runtime error '800a0005'
    Invalid procedure call or argument
    /AreaRiservata/AreaAnagrafica/Documenti/OutputFilePROVA1.asp, line 96


    <% Server.ScriptTimeout = 2000 %>

    <%

    Sub BuildUploadRequest(RequestBin)
    PosBeg = 1
    PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
    boundary = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
    boundaryPos = InstrB(1,RequestBin,boundary)
    Do until (boundaryPos=InstrB(RequestBin,boundary & getByteString("--")))
    Dim UploadControl
    Set UploadControl = CreateObject("Scripting.Dictionary")
    Pos = InstrB(BoundaryPos,RequestBin,getByteString("Conte nt-Disposition"))
    Pos = InstrB(Pos,RequestBin,getByteString("name="))
    PosBeg = Pos+6
    PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
    Name = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
    PosFile = InstrB(BoundaryPos,RequestBin,getByteString("filen ame="))
    PosBound = InstrB(PosEnd,RequestBin,boundary)
    If PosFile<>0 AND (PosFile<PosBound) Then
    PosBeg = PosFile + 10
    PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
    FileName = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
    UploadControl.Add "FileName", FileName
    Pos = InstrB(PosEnd,RequestBin,getByteString("Content-Type:"))
    PosBeg = Pos+14
    PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
    ContentType = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
    UploadControl.Add "ContentType",ContentType
    PosBeg = PosEnd+4
    PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
    Value = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
    Else
    Pos = InstrB(Pos,RequestBin,getByteString(chr(13)))
    PosBeg = Pos+4
    PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
    Value = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
    End If
    UploadControl.Add "Value" , Value
    UploadRequest.Add name, UploadControl
    BoundaryPos=InstrB(BoundaryPos+LenB(boundary),Requ estBin,boundary)
    Loop
    End Sub
    Function getByteString(StringStr)
    For i = 1 to Len(StringStr)
    char = Mid(StringStr,i,1)
    getByteString = getByteString & chrB(AscB(char))
    Next
    End Function
    Function getString(StringBin)
    getString =""
    For intCount = 1 to LenB(StringBin)
    getString = getString & chr(AscB(MidB(StringBin,intCount,1)))
    Next
    End Function
    %>



    <%
    Response.Expires=0
    Response.Buffer = TRUE
    Response.Clear
    byteCount = Request.TotalBytes
    RequestBin = Request.BinaryRead(byteCount)
    Dim UploadRequest
    Set UploadRequest = CreateObject("Scripting.Dictionary")
    BuildUploadRequest RequestBin
    contentType = UploadRequest.Item("blob").Item("ContentType")
    filepathname = UploadRequest.Item("blob").Item("FileName")
    filename = Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
    value = UploadRequest.Item("blob").Item("Value")


    Set objFS = Server.CreateObject("Scripting.FileSystemObject")
    Server.CreateObject("Scripting.FileSystemObject")
    strFileName = PercorsoScrittura '&(CARTELLA)
    strPath = objFS.GetParentFolderName(strFileName)
    strPath = strPath & "\" '& (cartella)

    If Not objFS.FolderExists(strPath) Then
    objFS.CreateFolder(strPath)
    End If

    Set ScriptObject = Server.CreateObject("Scripting.FileSystemObject")

    pathEnd = strFileName '&"\"
    cartella2 = Cartella&"\"
    'response.write(pathEnd):response.end


    ' ========INIZIO SCRIPT INSERIMENTO FILE SU CARTELLA
    Set MyFile = ScriptObject.CreateTextFile(pathEnd & filename)
    For i = 1 to LenB(value)
    MyFile.Write chr(AscB(MidB(value,i,1)))
    Next

    ' =====FINE SCRIPT INSERIMENTO FILE SU CARTELLA

    Myfile.Close
    response.Redirect(http)
    %>


    sono veramente disperato
    Pippo Giacalone
    giacalone@tin.it

  2. #2
    dimenticavo che la riga 96 e questa :

    MyFile.Write chr(AscB(MidB(value,i,1)))
    Pippo Giacalone
    giacalone@tin.it

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