ciao ragazzi, qualcuno che riesce a modificare questo codice affichè mostri un dropdown menu' ??
Codice PHP:
<div class="row_feed_loop js_parent_feed_entry {if isset($aFeed.feed_mini)} row_mini {else}{if isset($bChildFeed)} row1{else}{if isset($phpfox.iteration.iFeed)}{if is_int($phpfox.iteration.iFeed/2)}row1{else}row2{/if}{if $phpfox.iteration.iFeed == 1 && !PHPFOX_IS_AJAX} row_first{/if}{else}row1{/if}{/if}{/if} js_user_feed" id="js_item_feed_{$aFeed.feed_id}">
{if !Phpfox::isMobile() && ((defined('PHPFOX_FEED_CAN_DELETE')) || (Phpfox::getUserParam('feed.can_delete_own_feed') && $aFeed.user_id == Phpfox::getUserId()) || Phpfox::getUserParam('feed.can_delete_other_feeds'))}
<div class="feed_delete_link"><a href="#" class="action_delete js_hover_title" onclick="$.ajaxCall('feed.delete', 'id={$aFeed.feed_id}{if isset($aFeedCallback.module)}&module={$aFeedCallback.module}&item={$aFeedCallback.item_id}{/if}', 'GET'); return false;">
<span class="js_hover_info">{phrase var='feed.delete_this_feed'}</span></a></div>
{/if}
praticamente dopo quella variabile di frase ne vorrei includere altre in un menu' ..
grazie a chi saprà aiutarmi