Ho un codice per l'upload di file su un server, ma vorrei modificarlo per creare upload multipli ma non riesco a trovare il modo qui c'è il codice:
'variabili di configurazione
Dim folder
folder = "..\immagini" 'directory sul server con accesso in scrittura
'fine variabili di configurazione
Response.Expires=0
Response.Buffer = TRUE
Response.Clear
Sub BuildUploadRequest(RequestBin)
PosBeg = 1
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
boundary = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
boundaryPos = InstrB(1,RequestBin,boundary)
Do until (boundaryPos=InstrB(RequestBin,boundary & getByteString("--")))
Dim UploadControl
Set UploadControl = CreateObject("Scripting.Dictionary")
'Get an object name
Pos = InstrB(BoundaryPos,RequestBin,getByteString("Conte nt-Disposition"))
Pos = InstrB(Pos,RequestBin,getByteString("name="))
PosBeg = Pos+6
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
Name = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
PosFile = InstrB(BoundaryPos,RequestBin,getByteString("filen ame="))
PosBound = InstrB(PosEnd,RequestBin,boundary)
If PosFile<>0 AND (PosFile<PosBound) Then
PosBeg = PosFile + 10
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
FileName = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
UploadControl.Add "FileName", FileName
Pos = InstrB(PosEnd,RequestBin,getByteString("Content-Type:"))
PosBeg = Pos+14
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
ContentType = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
UploadControl.Add "ContentType",ContentType
PosBeg = PosEnd+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
Else
Pos = InstrB(Pos,RequestBin,getByteString(chr(13)))
PosBeg = Pos+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
End If
UploadControl.Add "Value" , Value
UploadRequest.Add name, UploadControl
BoundaryPos=InstrB(BoundaryPos+LenB(boundary),Requ estBin,boundary)
Loop
End Sub
Function getByteString(StringStr)
For i = 1 to Len(StringStr)
char = Mid(StringStr,i,1)
getByteString = getByteString & chrB(AscB(char))
Next
End Function
Function getString(StringBin)
getString =""
For intCount = 1 to LenB(StringBin)
getString = getString & chr(AscB(MidB(StringBin,intCount,1)))
Next
End Function
byteCount = Request.TotalBytes
RequestBin = Request.BinaryRead(byteCount)
Dim UploadRequest
Set UploadRequest = CreateObject("Scripting.Dictionary")
BuildUploadRequest RequestBin
contentType = UploadRequest.Item("blob").Item("ContentType")
filepathname = UploadRequest.Item("blob").Item("FileName")
filename = Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
value = UploadRequest.Item("blob").Item("Value")
'Create FileSytemObject Component
Set ScriptObject = Server.CreateObject("Scripting.FileSystemObject")
'Create and Write to a File
Set MyFile = ScriptObject.CreateTextFile(Server.mappath(folder) &"\"&filename)
For i = 1 to LenB(value)
MyFile.Write chr(AscB(MidB(value,i,1)))
Next
MyFile.Close
%>
<html>
<head>
<title>UPLOAD FILE</title>
</head>
<body>
<table border=0 width=360 bgcolor=#40576f cellspacing=1 align=center>
<tr>
<td width=400 align=center bgcolor=#40576f><FONT FACE="tahoma" color=#ffffff size=2>Il file <%=filename%> è stato uploadato con successo.</FONT></td>
</tr>
<tr>
<td width="400" height="30" bgcolor="#E6E6FF" align=center>< < UPLOAD DI UN ALTRO FILE</font></td>
</tr>
</table>
</body>
</html>
anche provando ad aggiungere
contentType = UploadRequest.Item("blob2").Item("ContentType")
filepathname = UploadRequest.Item("blob2").Item("FileName")
filename = Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
value = UploadRequest.Item("blob2").Item("Value")
è solo quest'ultimo file che viene mandato in rete.
Qualcuno può darmi una mano a capire come modificare questo file?
Grazie in anticipo
ross
Rispondi quotando
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