dov'è l'errore? (se c'è)

[s3th_one]

ho trovato in rete uno script che dovrebbe calcolare la differenza tra due date, una preimpostata e quella corrente, l'ho inserito in una pagina ma non mi funziona.
mi sapete dire dove è l'errore se c'è?

<?php
// This is a simple script to calculate the difference between two dates
// and express it in years, months and days
// 
// use as in: "my daughter is 4 years, 2 month and 17 days old" ... :-)
//
// Feel free to use this script for whatever you want
// 
// version 0.1 / 2002-10-3
//
// please send comments and feedback to webmaster@lotekk.net
//

// ****************************************************************************

// configure the base date here
$base_day		= 20;		// no leading "0"
$base_mon		= 8;		// no leading "0"
$base_yr		= 2005;		// use 4 digit years!

// get the current date (today) -- change this if you need a fixed date
$current_day		= date ("j");
$current_mon		= date ("n");
$current_yr		= date ("Y");

// and now .... calculate the difference! :-)

// overflow is always caused by max days of $base_mon
// so we need to know how many days $base_mon had
$base_mon_max		= date ("t",mktime (0,0,0,$base_mon,$base_day,$base_yr));

// days left till the end of that month
$base_day_diff 		= $base_mon_max - $base_day;

// month left till end of that year
// substract one to handle overflow correctly
$base_mon_diff 		= 12 - $base_mon - 1;

// start on jan 1st of the next year
$start_day		= 1;
$start_mon		= 1;
$start_yr		= $base_yr + 1;

// difference to that 1st of jan
$day_diff	= ($current_day - $start_day) + 1; 	// add today
$mon_diff	= ($current_mon - $start_mon) + 1;	// add current month
$yr_diff	= ($current_yr - $start_yr);

// and add the rest of $base_yr
$day_diff	= $day_diff + $base_day_diff;
$mon_diff	= $mon_diff + $base_mon_diff;

// handle overflow of days
if ($day_diff >= $base_mon_max)
{
	$day_diff = $day_diff - $base_mon_max;
	$mon_diff = $mon_diff + 1;
}

// handle overflow of years
if ($mon_diff >= 12)
{
	$mon_diff = $mon_diff - 12;
	$yr_diff = $yr_diff + 1;
}

// the results are here:

// $yr_diff  	--> the years between the two dates
// $mon_diff 	--> the month between the two dates
// $day_diff 	--> the days between the two dates

// ****************************************************************************

 /*simple output of the results 
print "The difference between ".$base_yr."-".$base_mon."-".$base_day." ";
print "and ".$current_yr."-".$current_mon."-".$current_day." is:";
print "

";

// this is just to make it look nicer
$years = "years";
$days = "days";
if ($yr_diff == "1") $years = "year";
if ($day_diff == "1") $days = "day";

// here we go
print $yr_diff." ".$years.", ";
print $mon_diff." month and ";
print $day_diff." ".$days;
*/
?>

[ken84]

io l'ho provato e mi funziona:

<?php
// This is a simple script to calculate the difference between two dates
// and express it in years, months and days
// 
// use as in: "my daughter is 4 years, 2 month and 17 days old" ... :-)
//
// Feel free to use this script for whatever you want
// 
// version 0.1 / 2002-10-3
//
// please send comments and feedback to [email]webmaster@lotekk.net[/email]
//

//  ****************************************
//************************************

// configure the base date here
$base_day        = 1;        // no leading "0"
$base_mon        = 1;        // no leading "0"
$base_yr        = 2005;        // use 4 digit years!

// get the current date (today) -- change this if you need a fixed date
$current_day        = date ("j");
$current_mon        = date ("n");
$current_yr        = date ("Y");

// and now .... calculate the difference! :-)

// overflow is always caused by max days of $base_mon
// so we need to know how many days $base_mon had
$base_mon_max        = date ("t",mktime (0,0,0,$base_mon,$base_day,$base_yr));

// days left till the end of that month
$base_day_diff         = $base_mon_max - $base_day;

// month left till end of that year
// substract one to handle overflow correctly
$base_mon_diff         = 12 - $base_mon - 1;

// start on jan 1st of the next year
$start_day        = 1;
$start_mon        = 1;
$start_yr        = $base_yr + 1;

// difference to that 1st of jan
$day_diff    = ($current_day - $start_day) + 1;     // add today
$mon_diff    = ($current_mon - $start_mon) + 1;    // add current month
$yr_diff    = ($current_yr - $start_yr);

// and add the rest of $base_yr
$day_diff    = $day_diff + $base_day_diff;
$mon_diff    = $mon_diff + $base_mon_diff;

// handle overflow of days
if ($day_diff >= $base_mon_max)
{
    $day_diff = $day_diff - $base_mon_max;
    $mon_diff = $mon_diff + 1;
}

// handle overflow of years
if ($mon_diff >= 12)
{
    $mon_diff = $mon_diff - 12;
    $yr_diff = $yr_diff + 1;
}

// the results are here:

// $yr_diff      --> the years between the two dates
// $mon_diff     --> the month between the two dates
// $day_diff     --> the days between the two dates

//  ****************************************
//************************************

 //simple output of the results 
print "The difference between [b]".$base_yr."-".$base_mon."-".$base_day."[/b] ";
print "and [b]".$current_yr."-".$current_mon."-".$current_day."[/b] is:";
print "

";

// this is just to make it look nicer
$years = "years";
$days = "days";
if ($yr_diff == "1") $years = "year";
if ($day_diff == "1") $days = "day";

// here we go
print $yr_diff." ".$years.", ";
print $mon_diff." month and ";
print $day_diff." ".$days;

?>

Output a video:

The difference between 2005-1-1 and 2006-1-3 is:

1 year, 0 month and 2 days

ciao

[s3th_one]

grazie ken!
in effetti c'erano alcuni blocchi commentati male in quello che avevo provato...

un'ultima cosa:

come potrei modificarlo in modo che, qualora la variabile anni risulti uguale a 0, nella stampata a video del risultato mi ometta il valore degli anni?

[ken84]

ti scrivo solo il pezzo interessato:

// here we go
if($yr_diff > 0)
 print $yr_diff." ".$years.", ";

print $mon_diff." month and ";
print $day_diff." ".$days;

?> 

non l'ho provata, comunque dovrebbe stamparti la scritta
"n years" solo se n > 0
Prova,nel caso fosse sbagliata chiedo venia...

ciao

[Quinn]

Originariamente inviato da ken84
ti scrivo solo il pezzo interessato:

// here we go
if($yr_diff > 0)
 print $yr_diff." ".$years.", ";

print $mon_diff." month and ";
print $day_diff." ".$days;

?> 

non l'ho provata, comunque dovrebbe stamparti la scritta
"n years" solo se n > 0
Prova,nel caso fosse sbagliata chiedo venia...

ciao

conviene <> infatti se fosse negativo..